Question: There are two bags A and B. Bag A contains 6 red balls and 10 green balls and bag B contains 4 red balls and 6 green balls. One bag is selected at random. From the selected bag one ball is drawn at random. What is the probability that the ball drawn is red? [SBI (SO) 2016]
Options:
A) $ \frac{27}{80} $
B) $ \frac{31}{80} $
C) $ \frac{39}{80} $
D) $ \frac{20}{80} $
E) $ \frac{33}{80} $
Show Answer
Answer:
Correct Answer: B
Solution:
- Probability of drawing one red from bag $ A=\frac{6}{16} $
Probability of drawing one red from bag $ B=\frac{4}{10} $
Probability to select one bag $ =\frac{1}{2} $
$ \therefore $ Required probably $ =\frac{1}{2}( \frac{6}{16}+\frac{4}{10} )=\frac{31}{80} $