Quantitative Aptitude Ques 449

Question: Directions: In each of the following questions there are two equations I and II. You have to solve both equations and give answer. [SBI (PO) 2015]

I. $ 2x^{2}-15x+28=0 $ II. $ 2y^{2}-21y+54=0 $

Options:

A) If $ x>y $

B) If $ x\ge y $

C) If $ x<y $

D) If $ x\le y $

E) If $ x=y $ or relation cannot be established

Show Answer

Answer:

Correct Answer: C

Solution:

  • I. $ 2x^{2}-15x+28=0 $

$ \Rightarrow $ $ 2x^{2}-8x-7x+28=0 $

$ \Rightarrow $ $ 2x,(x-4)-7,(x-4)=0 $
$ \Rightarrow , $ $ x=4, $ $ \frac{7}{2} $ II. $ 2y^{2}-21y+54=0 $

$ \Rightarrow $ $ 2y^{2}-12y-9y+54=0 $

$ \Rightarrow $ $ 2y,(y-6)-9,(y-6)=0 $
$ \Rightarrow , $ $ y=6, $ $ \frac{9}{2} $

$ \therefore $ $ x<y $