Quantitative Aptitude Ques 392

Question: Direction: Read the following information carefully and answer the given question. There are 5 red balls, 6 green balls and 7 blue balls in a box.

If three balls are drawn randomly what is the probability that one of them is red and the remaining two are blue?

Options:

A) 5/34

B) 25/136

C) 35/272

D) 45/272

E) 15/136

Show Answer

Answer:

Correct Answer: C

Solution:

  • Required probability $ =\frac{{}^{5}C _1\times {}^{7}C _2}{{}^{18}C _3}=\frac{5\times 21}{816}=\frac{35}{272} $
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