Quantitative Aptitude Ques 392
Question: Direction: Read the following information carefully and answer the given question. There are 5 red balls, 6 green balls and 7 blue balls in a box.
If three balls are drawn randomly what is the probability that one of them is red and the remaining two are blue?
Options:
A) 5/34
B) 25/136
C) 35/272
D) 45/272
E) 15/136
Show Answer
Answer:
Correct Answer: C
Solution:
- Required probability $ =\frac{{}^{5}C _1\times {}^{7}C _2}{{}^{18}C _3}=\frac{5\times 21}{816}=\frac{35}{272} $
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