SATHEE: Quantitative Aptitude Ques 382

Quantitative Aptitude Ques 382

Question: Directions: In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer.

I. $ x^{2}+11x+30=0 $ II. $ y^{2}+7y+12=0 $

Options:

A) If $ x>y $

B) If $ x\ge y $

C) If $ x<y $

D) If $ x\le y $

E) If x = y or the relationship cannot be established

Show Answer

Answer:

Correct Answer: C

Solution:

I. $ x^{2}+11x+30=0 $

$ \Rightarrow $ $ x^{2}+6x+5x+30=0 $

$ \Rightarrow $ $ x,(x+6)+5,(x+6)=0 $

$ \Rightarrow $ $ (x+6)(x+5)=0 $

$ \Rightarrow $ $ x=-,6, $ $ -,5 $ II. $ y^{2}+7y+12=0 $

$ \Rightarrow $ $ y^{2}+4y+3y+12=0 $

$ \Rightarrow $ $ y,(y+4)+3,(y+4)=0 $

$ \Rightarrow $ $ (y+4)(y+3)=0 $

$ \Rightarrow $ $ y=-,4,-,3 $ Hence, $ y>x $

Quantitative Aptitude Ques 381

Quantitative Aptitude Ques 383

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