A) $ \frac{1}{32} $
B) $ \frac{1}{16} $
C) $ \frac{3}{16} $
D) $ \frac{5}{16} $
Correct Answer: C
$ \therefore $ Required probability $ ={}^{5}C _3{{( \frac{1}{2} )}^{3}}{{( \frac{1}{2} )}^{2}} $ $ =\frac{5\times 4}{2\times 1}{{( \frac{1}{2} )}^{5}} $ $ =10.\frac{1}{2^{5}}=\frac{5}{16} $