Question: A jogger running at 9 km/h alongside a railway track is 240 m ahead of the engine of a 120 m long train running at 45 km/h in the same direction. In how much time will the train pass the jogger?
Options:
A) 70 s
B) 36 s
C) 56 s
D) 18 s
Show Answer
Answer:
Correct Answer: B
Solution:
- Total speed of jogger and train
$ =45-9=36,km/h $
(because train and jogger is in same direction)
Total speeds = 36km/h $ =36\times \frac{5}{18}m/s=10,m/s $
$ \therefore $ Time taken by train to pass the jogger
$ =\frac{Total,distance}{Total,speed}=\frac{(120+240)}{10}=\frac{360}{10}s=36,s $