Quantitative Aptitude Ques 363

Question: Two pipes can fill a tank in 10 h and 16 h, respectively. A third pipe can empty the tank in 40 h. If all the three pipes are opened and function simultaneously then in how much time the tank will be full?

Options:

A) $ 6\frac{1}{11}h $

B) $ 9\frac{9}{11}h $

C) $ 8\frac{9}{11}h $

D) $ 7\frac{3}{11}h $

E) $ 6\frac{5}{11}h $

Show Answer

Answer:

Correct Answer: D

Solution:

  • Part of the tank filled in 1 min $ =\frac{1}{10}+\frac{1}{16}-\frac{1}{40} $ $ =\frac{8+5-2}{80}=\frac{11}{80} $ Thus, required time for the tank to be filled $ =\frac{80}{11}=7\frac{3}{11}h $
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