Question: A and B can do a piece of work in 15 days. B and C can do the same work in 10 days and A and C can do the same in 12 days. Time taker by A, B and C together to do the job is
Options:
A) 9 days
B) 8 days
C) 4 days
D) 5 days
Show Answer
Answer:
Correct Answer: B
Solution:
- $ (A+B)’s $ one day work $ =\frac{1}{15} $
$ (B+C)’s $ one day work $ =\frac{1}{10} $
$ (A+C)’s $ one day work $ =\frac{1}{12} $
$ \therefore $ $ 2,(A+B+C)=\frac{1}{15}+\frac{1}{10}+\frac{1}{12} $
$ \Rightarrow $ $ 2,(A+B+C)=\frac{4+6+5}{60}=\frac{15}{60} $
$ \Rightarrow $ $ 2,(A+B+C)=\frac{1}{4} $
$ \Rightarrow $ $ A+B+C=\frac{1}{8} $
$ \therefore $ A, B and C together will finish the work in 8 days.