Quantitative Aptitude Ques 323

Question: AB is a diameter of a circle having centre at O. P is a point on the circumference of the circle. If $ \angle POA=120{}^\circ , $ then measure of $ \angle PBO $ is

Options:

A) $ 68{}^\circ $

B) $ 60{}^\circ $

C) $ 75{}^\circ $

D) $ 70{}^\circ $

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Answer:

Correct Answer: B

Solution:

  • Given, AB is diameter and $ \angle POA=120{}^\circ $

$ \therefore $ $ \angle POB=180{}^\circ -120{}^\circ =60{}^\circ $ $ \because $ $ OP=OB=r $

$ \therefore $ $ \angle PBO=\angle OPB $ $ =\frac{180{}^\circ -60{}^\circ }{2}=60{}^\circ $