Quantitative Aptitude Ques 285
Question: In the figure given below, $ AB\parallel CD $ and EF intersects them. Then, the value of x is
Options:
A) $ 18{}^\circ $
B) $ 14{}^\circ $
C) $ 28{}^\circ $
D) $ 24{}^\circ $
Show Answer
Answer:
Correct Answer: C
Solution:
- According to the question, From figure, $ \angle EOB=\angle EMD=2x{}^\circ $ [corresponding angel] Now, $ \angle EMD+\angle EMC=180{}^\circ $
$ \therefore $ $ 4x+12{}^\circ +2x=180{}^\circ $
$ \Rightarrow $ $ 6x+12{}^\circ =180{}^\circ $
$ \Rightarrow $ $ 6x=168{}^\circ $
$ \Rightarrow $ $ x=\frac{168{}^\circ }{6} $
$ \Rightarrow $ $ x=28{}^\circ $
BETA
