Quantitative Aptitude Ques 280

Question: The factors of $ (a^{2}+4b^{2}+4b-4ab-2a-8) $ are

Options:

A) $ (a-2b-4)(a-2b+2) $

B) $ (a-b+2)(a-4b-4) $

C) $ (a+2b-4)(a+2b+2) $

D) $ (a+2b-1)(a-2b+1) $

Show Answer

Answer:

Correct Answer: A

Solution:

  • $ a^{2}+4b^{2}+4b-4ab-2a-8 $ On adding and subtracting 2a and 4b, we get $ a^{2}+4b^{2}+4b-4ab-2a-8+2a-2a-4b+4b $ $ =a,(a-2b+2)-2b,(a-2b+2)-4,(a-2b+2) $ $ =(a-2b+2)(a-2b-4) $
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