Quantitative Aptitude Ques 271

Question: The speed of the boat in still water is 24 km/h and the speed of the stream is 4 km/h. The time taken by the boat to travel from A to B downstream is 36 min less than the time taken by the same boat to travel from B to C upstream. If the distance between A and B is 4 km more than the distance between B and C, what is the distance between A and B?

Options:

A) 112 km

B) 140 km

C) 56 km

D) 84 km

E) 28 km

Show Answer

Answer:

Correct Answer: C

Solution:

  • Speed of boat in still water = 24 km/h Speed of stream = 4 km/h Speed of boat in downstream = 28 km/h Speed of boat in upstream = 20 km/h Again, let the distance between B and C = x km Then, distance between A and B $ =(x+4),km $ Now, $ \frac{x}{20}-\frac{(x+4)}{28}=\frac{36}{60} $ [difference in time]

$ \Rightarrow $ $ \frac{7x-5,(x+4)}{140}=\frac{3}{5} $

$ \Rightarrow $ $ 2x-20=84 $

$ \Rightarrow $ $ 2x=84+20 $

$ \Rightarrow $ $ x=\frac{104}{2}=52km $

$ \therefore $ Required distance $ =52+4=56,km $

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