Quantitative Aptitude Ques 2488

Question: Directions: In each of the following questions two equations are given. You have to solve both the equations and find out values of x, y and give answer. [NICL (AO) 2014]

I. $ x^{2}-10x+21=0 $ II. $ y^{2}-16y+63=0 $

Options:

A) If $ x>y $

B) If $ x\le y $

C) If $ x<y $

D) If $ x\ge y $

E) If relationship between x and y cannot be determined

Show Answer

Answer:

Correct Answer: B

Solution:

  • I. $ x^{2}-10x+21=0 $ $ x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}=\frac{10\pm \sqrt{100-84}}{2}=7, $ 3 II. $ y^{2}-16y+63=0 $ $ y=\frac{16\pm \sqrt{256-252}}{2}=\frac{16\pm 2}{2}=9, $ 7

$ \therefore $ $ x\le y $