Question: Directions: In each of the following questions two equations are given. You have to solve both the equations and find out values of x, y and give answer. [NICL (AO) 2014]
I. $ x^{2}-10x+21=0 $
II. $ y^{2}-16y+63=0 $
Options:
A) If $ x>y $
B) If $ x\le y $
C) If $ x<y $
D) If $ x\ge y $
E) If relationship between x and y cannot be determined
Show Answer
Answer:
Correct Answer: B
Solution:
- I. $ x^{2}-10x+21=0 $
$ x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}=\frac{10\pm \sqrt{100-84}}{2}=7, $ 3
II. $ y^{2}-16y+63=0 $
$ y=\frac{16\pm \sqrt{256-252}}{2}=\frac{16\pm 2}{2}=9, $ 7
$ \therefore $ $ x\le y $