Quantitative Aptitude Ques 2482

Question: If O is the circumcentre of a $ \Delta ,ABC $ lying inside the triangle, then $ \angle OBC+\angle BAC $ is equal to

Options:

A) $ 60{}^\circ $

B) $ 90{}^\circ $

C) $ 110{}^\circ $

D) $ 120{}^\circ $

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Answer:

Correct Answer: B

Solution:

  • Let $ \angle A=x{}^\circ $

$ \therefore $ $ \angle BOC=2x{}^\circ $ and $ \angle BOE=x{}^\circ $ Again, let $ \angle OBE=y{}^\circ $ and we have $ \angle OEB=90{}^\circ $ In $ \Delta BOE, $ $ x{}^\circ +y{}^\circ +90{}^\circ =180{}^\circ $

$ \Rightarrow $ $ x{}^\circ +y{}^\circ =90{}^\circ $

$ \therefore $ $ \angle OBC+\angle BAC=90{}^\circ $