SATHEE: Quantitative Aptitude Ques 2462

Quantitative Aptitude Ques 2462

Question: A trader purchases a watch and a wall clock of Rs. 390. He sells them making a profit of 10% on the watch and 15% on the wall clock. He earns a profit of Rs. 51.50. The difference between the original prices of the wall clock and the watch is equal to [NICL (AO) 2015]

Options:

A) Rs. 80

B) Rs. 100

C) Rs. 110

D) Rs. 120

E) Rs. 150

Show Answer

Answer:

Correct Answer: C

Solution:

Let the CP of watch be Rs. x.

$ \therefore $ CP of a wall clock $ =Rs.(390-x) $ Now, according to the question, 10% of $ x+50% $ of $ (390-x)=51.50 $

$ \Rightarrow $ $ \frac{x\times 10}{100}+\frac{(390-x)\times 15}{100}=51.50 $

$ \Rightarrow $ $ 10x+5850-15x=5150 $

$ \Rightarrow $ $ -,5x=-700 $
$ \Rightarrow $ $ x=140 $

$ \therefore $ CP of watch = Rs. 140 and CP of wall clock $ =Rs.(390-140)=Rs.250 $

$ \therefore $ Difference between their prices $ =250-140=Rs.,110 $

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