Quantitative Aptitude Ques 2443

Question: In the given figure, O is the centre of a circle and diameter AB bisects the chord CD at a point such that $ CE=ED=8,cm $ and $ EB=4cm. $ The radius of the circle is

Options:

A) 10 cm

B) 12 cm

C) 6 cm

D) 8 cm

Show Answer

Answer:

Correct Answer: A

Solution:

  • Let the radius of the circle be r cm. Then, OD = OB = r cm, $ OE=(r-4),cm $ and ED = 8 cm Now, $ OD^{2}=OE^{2}+ED^{2} $

$ \Rightarrow $ $ r^{2}={{(r-4)}^{2}}+8^{2} $

$ \Rightarrow $ 8r = 80

$ \therefore $ r = 10 cm

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