A) $ \tan ,B+\tan ,A+\tan ,C $
B) $ \tan ,B-\tan ,A+\tan ,C $
C) $ \tan ,B-\tan ,A-\tan ,C $
D) $ \tan ,B+\tan ,A-\tan ,C $
Correct Answer: C
$ \therefore $ Total age = 8x According to the question, $ \frac{8x-(21+23)+(Age,of,two,new,men)}{8}=x+2 $
$ \Rightarrow $ $ 8x-44+(\text{Age of two new men})=8x+16 $
$ \Rightarrow $ $ Ageoftwonewmen=16+44=60yr $
$ \therefore $ Average age $ =\frac{60}{2}=30,yr $