Question: A is twice as good a workman as B and together they finish a piece of work in 14 days. The number of days taken by A alone to finish the work is
Options:
A) 11
B) 21
C) 28
D) 42
Show Answer
Answer:
Correct Answer: B
Solution:
- (A’s 1 day’s work): (B’s 1 day’s work) = 2 : 1
(A + B)’s 1 day’s work $ =\frac{1}{14} $
Divide $ =\frac{1}{14} $ in the ratio 2: 1
$ \therefore $ As 1 day’s work $ =( \frac{1}{14}\times \frac{2}{3} )=\frac{1}{21} $
Hence, A alone can finish the work in 21 days.