Question: Pradeep invested 20% more than Mohit. Mohit invested 10% less than Raghu. If the total sum of their investment is Rs. 17880, then how much amount did Raghu invest? [Corporation Bank (PO) 2011]
Options:
A) Rs. 6000
B) Rs. 8000
C) Rs. 7000
D) Rs. 5000
E) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
- Let the amount Raghu invested be Rs. x
Then, amount invested by Mohit
$ =x\times \frac{90}{100}=\frac{9x}{10} $
Now, amount invested by Pradeep
$ =\frac{9x}{10}\times \frac{120}{100}=\frac{108x}{100}=\frac{27x}{25} $
$ \therefore $ $ x+\frac{9x}{10}+\frac{27x}{25}=17880 $
$ \Rightarrow $ $ \frac{50x+45x+54x}{50}=17880 $
$ \Rightarrow $ $ 149x=17880\times 50 $
$ \Rightarrow $ $ x=\frac{894000}{149} $
$ \therefore $ $ x=Rs.,6000 $