A) 5 days
B) $ 7\frac{5}{6}days $
C) 10 days
D) $ 15\frac{2}{3}days $
Correct Answer: C
$ \therefore $ $ (A+B)’s $ 1 day’s of work $ =\frac{1}{12} $ Similarly, $ (B+C)’s $ 1 day’s of work $ =\frac{1}{15} $ and $ (C+A)’s $ 1 day’s of work $ =\frac{1}{20} $
$ \therefore $ $ 2,(A+B+C)’s $ 1 day’s of work, $ =\frac{1}{12}+\frac{1}{15}+\frac{1}{20}=\frac{5+4+3}{60}=\frac{1}{5} $
$ \therefore $ $ (A+B+C)’s $ can complete the work in 10 days.