Question: A girl of height 90 cm is walking away from the base of a lamp-post at a speed of 1.2 m/s. If the lamp is 3.6 m above the ground, then find the length of her shadow after 4 s.
Options:
A) 8 m
B) 1.6 m
C) 2.8 m
D) 2 m
Show Answer
Answer:
Correct Answer: B
Solution:
- Let length of shadow = DE = x m
BD = Distance covered by the girl in 4 s
$ =1.2\times 4=4.8m $
Also, in $ \Delta ABE $ and $ \Delta CDE $
and $ \angle B=\angle D $
$ \Rightarrow $ $ \angle A=\angle C $ and $ \angle E=\angle E $
$ \therefore $ $ \Delta ABE=\Delta CDE $
$ \therefore $ $ \frac{BE}{DE}=\frac{AB}{CD} $
$ \Rightarrow $ $ \frac{4.8+x}{x}=\frac{3.6}{0.9} $
$ \Rightarrow $ $ 4.8+x=4x $
$ \Rightarrow $ $ x=1.6,m $