Quantitative Aptitude Ques 239
Question: Two circles touch externally. The sum of their areas is $ 130\pi ,cm^{2} $ and the distance between their centres is 14 cm. The radius of the smaller circle is
Options:
A) 2 cm
B) 3 cm
C) 4 cm
D) 5 cm
Show Answer
Answer:
Correct Answer: B
Solution:
- Here, Now, $ \pi ,{{(14-R)}^{2}}+\pi ,R^{2}=130\pi $ $ 196+R^{2}-28R+R^{2}=130 $
$ \Rightarrow $ $ 2R^{2}-28R+66=0 $
$ \Rightarrow $ $ R^{2}-14R+33=0 $
$ \Rightarrow $ $ R^{2}-11R-3R+33=0 $
$ \Rightarrow $ $ R,(R-11)-3,(R-11)=0 $
$ \Rightarrow $ $ R=11 $
$ \therefore $ Radius of smaller circle $ =14-11=3,cm $
BETA
