A) 15 min
B) 10 min
C) 5 min
D) 9 min
Correct Answer: D
$ \therefore $ Part of the tank filled by A in 30 min $ =\frac{2}{75}\times 30=\frac{4}{5} $ Remaining part $ =1-\frac{4}{5}=\frac{1}{5} $ Now, 1 part is filled by pipe B in 45 min.
$ \therefore $ $ \frac{1}{5} $ part is filled in $ 45\times \frac{1}{5}=9,\min $ Hence, the pipe B should be turned off after 9 min.