Question: If N is the greatest number that will divide 1305, 4665 and 6905 leaving the same remainder, in each case. Then, sum of the digits in N is
Options:
A) 4
B) 5
C) 6
D) 8
Show Answer
Answer:
Correct Answer: A
Solution:
- The greatest number N = HCF of $ (1305-x), $ $ (4665-x) $ and $ (6905-x), $ where x is the remainder,
= HCF of $ (4665-1305), $ $ (6905-4665) $ and $ (6905-1305) $
HCF of 3360, 2240 and 5600
Again,
$ \therefore $ $ N=1120 $
Sum of digits $ =1+1+2+0=4 $