Quantitative Aptitude Ques 2385

Question: In how many ways can 5 boys and 5 girls sit in a circle, so that no two boys sit together?

Options:

A) $ 5!,\times ,5! $

B) $ 4!,\times ,5! $

C) $ \frac{5!\times 5!}{2} $

D) None of these

Show Answer

Answer:

Correct Answer: B

Solution:

  • First we fix the alternate position of the girls. The number of ways in which five girls can be seated around the circle $ =(5-1)!=4!. $ Now, 5 boys can be seated in five vacant place in 51 ways.

$ \therefore $ Required number of ways $ =4!,\times 5! $

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