SATHEE: Quantitative Aptitude Ques 2381

Quantitative Aptitude Ques 2381

Question: Consider the following statements

I. Let ABCD be a parallelogram which is not a rectangle. Then, $ 2,(AB^{2}+BC^{2})\ne AC^{2}+BD^{2} $ II. If ABCD is a rhombus with AB = 4 cm, then $ AC^{2}+BD^{2}=n^{3} $ for some positive integer n. Which of the above statements Ware Correct?

Options:

A) Only I

B) Only II

C) Both I and II

D) Neither I nor II

Show Answer

Answer:

Correct Answer: B

Solution:

I. ABCD is a parallelogram, then $ AC^{2}+BD^{2}=2,(AB^{2}+BC^{2}) $ II. ABCD is a rhombus and diagonals AC and BD bisect each other.

$ \therefore $ $ AO=OC $ and $ OB=OD $ In $ \Delta AOB, $ $ AB^{2}=AO^{2}+OB^{2} $

$ \Rightarrow $ $ {{(4)}^{2}}={{( \frac{AC}{2} )}^{2}}+{{( \frac{BD}{2} )}^{2}} $

$ \therefore $ $ AC^{2}+BD^{2}=64={{(4)}^{3}} $ i.e. $ n^{3} $

Quantitative Aptitude Ques 2380

Quantitative Aptitude Ques 2382

Quantitative Aptitude Ques 2381

Question: Consider the following statements

Options:

Answer:

Solution:

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