Quantitative Aptitude Ques 2378
Question: Directions: In the given questions two equations numbered I and II are given. You have to solve both the equations and mark the appropriate answer. [NICL (AO) 2014]
I. $ 9x^{2}-36x+35=0 $ II. $ 2y^{2}-15y+27=0 $
Options:
A) $ x\ge y $
B) $ x<y $
C) $ x>y $
D) $ x\le y $
E) relationship between x and y cannot be determined
Show Answer
Answer:
Correct Answer: B
Solution:
- I. $ 9x^{2}-36x+35=0 $
$ \Rightarrow $ $ 9x^{2}-21x-15x+35=0 $
$ \Rightarrow $ $ 3x,(3x-7)-5,(3x-7)=0 $
$ \Rightarrow $ $ (3x-7)(3x-5)=0 $
$ \Rightarrow $ $ x=\frac{7}{3}, $ $ \frac{5}{3} $ II. $ 2y^{2}-15y+27=0 $
$ \Rightarrow $ $ 2y^{2}-6y-9y+27=0 $
$ \Rightarrow $ $ 2y,(y-3)-9,(y-3)=0 $
$ \Rightarrow $ $ (y-3)(2y-9)=0 $
$ \Rightarrow $ $ y=3, $ $ \frac{9}{2} $
$ \therefore $ $ x<y $