Quantitative Aptitude Ques 2377

Question: Directions: In the given questions two equations numbered I and II are given. You have to solve both the equations and mark the appropriate answer. [NICL (AO) 2014]

I. $ 3x^{2}-26x-29=0 $ II. $ 6y^{2}-15y+25=0 $

Options:

A) $ x\ge y $

B) $ x<y $

C) $ x>y $

D) $ x\le y $

E) relationship between x and y cannot be determined

Show Answer

Answer:

Correct Answer: E

Solution:

  • I. $ 3x^{2}-26x-29=0 $

$ \Rightarrow $ $ 3x^{2}-29x+3x-29=0 $

$ \Rightarrow $ $ x,(3x-29)+1,(3x-29)=0 $

$ \Rightarrow $ $ (3x-29)(x+1)=0 $
$ \Rightarrow $ $ x=\frac{29}{3}, $ $ -1 $ II. $ 6y^{2}-25y+25=0 $

$ \Rightarrow $ $ 6y^{2}-15y-10y+25=0 $

$ \Rightarrow $ $ 3y,(2y-5)-5,(2y-5)=0 $

$ \Rightarrow $ $ (2y-5)(3y-5)=0 $

$ \Rightarrow $ $ y=\frac{5}{2}, $ $ y=\frac{5}{3} $

$ \therefore $ Relationship between x and y can’t be determined.