A) $ 4\frac{1}{2}h $
B) $ 4\frac{2}{3}h $
C) $ 3\frac{1}{2}h $
D) $ 3\frac{1}{4}h $
Correct Answer: B
$ \therefore $ Part filled by $ (A+B) $ in $ 4h=\frac{5}{12}\times 2=\frac{5}{6} $ Remaining part $ =1-\frac{5}{6}=\frac{1}{6} $ Now, it is the turn of A. Time taken by A to fill $ \frac{1}{6} $ part of the tank $ =\frac{1}{6}\times 4=\frac{2}{3}h $
$ \therefore $ Total time taken $ =( 4+\frac{2}{3} )h=4\frac{2}{3}h $