Quantitative Aptitude Ques 2361
Question: P and Q together can do a job in 6 days. Q and R can finish the same job in 60/7 days. P started the work and worked for 3 days. Q and R continued for 6 days. Then, the difference of days in which R and P can complete the job, is
Options:
A) 15
B) 10
C) 8
D) 12
Show Answer
Answer:
Correct Answer: B
Solution:
- Work done by P and Q in 6 days $ =6\times \frac{7}{60}=\frac{7}{10} $
$ \therefore $ Remaining $ =1-\frac{7}{10}=\frac{3}{10}th $ of work done by P in 3 days. Since, P alone can do the work in 10 days.
$ \therefore $ Q alone can do the work in $ \frac{10\times 6}{10-6}=15,days $
$ \therefore $ R alone can do the work in $ \frac{15\times \frac{60}{7}}{15-\frac{60}{7}}=20,days $
$ \therefore $ Difference $ =20-10=10days $
BETA
