Quantitative Aptitude Ques 2361

Question: P and Q together can do a job in 6 days. Q and R can finish the same job in 60/7 days. P started the work and worked for 3 days. Q and R continued for 6 days. Then, the difference of days in which R and P can complete the job, is

Options:

A) 15

B) 10

C) 8

D) 12

Show Answer

Answer:

Correct Answer: B

Solution:

  • Work done by P and Q in 6 days $ =6\times \frac{7}{60}=\frac{7}{10} $

$ \therefore $ Remaining $ =1-\frac{7}{10}=\frac{3}{10}th $ of work done by P in 3 days. Since, P alone can do the work in 10 days.

$ \therefore $ Q alone can do the work in $ \frac{10\times 6}{10-6}=15,days $

$ \therefore $ R alone can do the work in $ \frac{15\times \frac{60}{7}}{15-\frac{60}{7}}=20,days $

$ \therefore $ Difference $ =20-10=10days $

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