Quantitative Aptitude Ques 2355
Question: If $ x+\frac{1}{x}=1, $ then the value of $ \frac{x^{2}+3x+1}{x^{2}+7x+1} $ is
Options:
A) $ \frac{1}{2} $
B) $ \frac{3}{7} $
C) 2
D) 1
Show Answer
Answer:
Correct Answer: A
Solution:
- Given, $ x+\frac{1}{x}=1 $
$ \frac{x^{2}+3x+1}{x^{2}+7x+1}=\frac{x( x+\frac{1}{x} )+3x}{x( x+\frac{1}{x} )+7x}=\frac{x+3x}{x+7x} $
$ =\frac{4x}{8x}=\frac{1}{2}=1:2 $