Question: A work can be completed by P and Q in 12 days, Q and R in 15 days, R and P in 20 days. In how many days P alone can finish the work?
Options:
A) 10
B) 20
C) 30
D) 60
Show Answer
Answer:
Correct Answer: C
Solution:
- $ (P+Q)’s $ 1 day’s work $ =\frac{1}{12} $ ….(i)
$ (Q+R)’s $ 1 day’s work $ =\frac{1}{15} $ ….(ii)
$ (R+P)’s $ 1 day’s work $ =\frac{1}{20} $ ….(iii)
On adding Eqs. (i), (ii) and (iii), we get
$ 2(P+Q+R)’s $ 1 day’s work
$ =\frac{1}{12}+\frac{1}{15}+\frac{1}{20}=\frac{5+4+3}{60}=\frac{12}{60}=\frac{1}{5} $
$ \therefore $ $ (P+Q+R)’s $ 1 day’s work $ =\frac{1}{10} $ ….(iv)
$ \therefore $ P’s 1 day s work $ =\frac{1}{10}-\frac{1}{15}=\frac{3-2}{30}=\frac{1}{30} $
So, P alone will complete the work in 30 days.