Quantitative Aptitude Ques 2341
Question: A basket contains three red and four green balls. If four balls are drawn at random from the basket, what is the probability that two are red and two are green?
Options:
A) $ \frac{4}{7} $
B) $ \frac{2}{7} $
C) $ \frac{18}{35} $
D) $ \frac{3}{14} $
E) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
- Required probability
$ =\frac{{}^{3}C _2\times {}^{4}C _2}{{}^{7}C _4}=\frac{3\times 6}{7\times 5}=\frac{18}{35} $