Quantitative Aptitude Ques 2333

Question: Directions : In these questions, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate answer. [NICL (AO) 2014]

I. $ 22x^{2}-x-6=0 $ II. $ 63y^{2}-11y-40=0 $

Options:

A) If $ x\le y $

B) lf $ x<y $

C) If $ x>y $

D) If relationship between x and y cannot be established

E) lf $ x\ge y $

Show Answer

Answer:

Correct Answer: D

Solution:

  • I. $ 22x^{2}-x-6=0 $ By splitting the middle term, $ 22x^{2}+11x-12x-6=0 $ $ 11x,(2x+1)-6,(2x+1)=0 $ $ (11x-6)(2x+1)=0 $ $ x=\frac{6}{11}, $ $ x=-\frac{1}{2} $ value of $ x=( \frac{6}{11},,-\frac{1}{2} ) $ II. $ 63y^{2}-11y-40=0 $ By splitting the middle term. $ 63y^{2}+45y-56y-40=0 $ $ 9y,(7y+5)-8,(7y+5)=0 $ $ (9y-8)(7y+5)=0 $ $ y=\frac{8}{9}, $ $ y=-\frac{5}{7} $ value of $ y=( \frac{8}{9},-\frac{5}{7} ) $ Hence, relationship between x and y cannot be established.