Quantitative Aptitude Ques 2333
Question: Directions : In these questions, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate answer. [NICL (AO) 2014]
I. $ 22x^{2}-x-6=0 $ II. $ 63y^{2}-11y-40=0 $
Options:
A) If $ x\le y $
B) lf $ x<y $
C) If $ x>y $
D) If relationship between x and y cannot be established
E) lf $ x\ge y $
Show Answer
Answer:
Correct Answer: D
Solution:
- I. $ 22x^{2}-x-6=0 $ By splitting the middle term, $ 22x^{2}+11x-12x-6=0 $ $ 11x,(2x+1)-6,(2x+1)=0 $ $ (11x-6)(2x+1)=0 $ $ x=\frac{6}{11}, $ $ x=-\frac{1}{2} $ value of $ x=( \frac{6}{11},,-\frac{1}{2} ) $ II. $ 63y^{2}-11y-40=0 $ By splitting the middle term. $ 63y^{2}+45y-56y-40=0 $ $ 9y,(7y+5)-8,(7y+5)=0 $ $ (9y-8)(7y+5)=0 $ $ y=\frac{8}{9}, $ $ y=-\frac{5}{7} $ value of $ y=( \frac{8}{9},-\frac{5}{7} ) $ Hence, relationship between x and y cannot be established.
BETA
