Quantitative Aptitude Ques 2332
Question: Directions : In these questions, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate answer. [NICL (AO) 2014]
I. $ 40x^{2}-47x+12=0 $ II. $ 5y^{2}-51y+54=0 $
Options:
A) If $ x\le y $
B) lf $ x<y $
C) If $ x>y $
D) If relationship between x and y cannot be established
E) lf $ x\ge y $
Show Answer
Answer:
Correct Answer: B
Solution:
- I. $ 40x^{2}-47x+12=0 $ By splitting the middle term, $ 40x^{2}-32x+15x+12=0 $ $ 8x,(5x-4)-3,(5x-4)=0 $ $ (8x-3)(5x-4)=0\Rightarrow x=\frac{3}{8}, $ $ \frac{4}{5} $ II. $ 5y^{2}-51y+54=0 $ By splitting the middle term, $ 5y^{2}-45y-6y+54=0 $ $ 5y,(y-9)-6,(y-9)=0 $ $ (5y-6)(y-9)=0\Rightarrow y=\frac{6}{5}, $ 9 Hence, $ y>x $
BETA
