Quantitative Aptitude Ques 2311

Question: If $ \sqrt{3}=1.7321, $ then the value of $ \sqrt{192}-\frac{1}{2}\sqrt{48}-\sqrt{75}, $ (correct to 3 places of decimal) is

Options:

A) 8.661

B) 4.331

C) 1.7321

D) $ -1.746 $

Show Answer

Answer:

Correct Answer: C

Solution:

  • Expression $ =\sqrt{192}-\frac{1}{2}\sqrt{48}-\sqrt{75} $ $ =\sqrt{64\times 3}-\frac{1}{2}\sqrt{16\times 3}-\sqrt{25\times 3} $ $ =8\sqrt{3}-\frac{1}{2}\times 4\sqrt{3}-5\sqrt{3} $ $ =8\sqrt{3}-2\sqrt{3}-5\sqrt{3}=\sqrt{3}=1.7321 $
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