Quantitative Aptitude Ques 230

Question: The area of the parallelogram whose length is 30 cm, width is 20 cm and one diagonal is 40 cm, is

Options:

A) $ 100\sqrt{15},cm^{2} $

B) $ 150\sqrt{15},cm^{2} $

C) $ 200\sqrt{15},cm^{2} $

D) $ 300\sqrt{15},cm^{2} $

Show Answer

Answer:

Correct Answer: B

Solution:

  • Both of the triangles made by the diagonals of the parallelogram will be equal in area. Now, area of $ \Delta ABC=\sqrt{s,(s-a)(s-b)(s-c)} $ $ =\sqrt{45,(5),(15),(25)}=75\sqrt{15},cm^{2} $ Thus, area of the parallelogram ABCD $ =2\times 75\sqrt{15},cm^{2}=150\sqrt{15},cm^{2} $
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