Quantitative Aptitude Ques 2292

Question: Directions: In the given question two equations numbered I and II are given. You have to solve both the equations and mark the appropriate answer.

I. $ x^{2}+7x+12=0 $ II. $ 2y^{2}+11y+15=0 $

Options:

A) If $ x\ge y $

B) If $ x<y $

C) If $ x>y $

D) If $ x\le y $

E) relationship between x and y cannot be determined

Show Answer

Answer:

Correct Answer: D

Solution:

  • I. $ x^{2}+7x+12=0 $

$ \Rightarrow $ $ x^{2}+4x+3x+12=0 $

$ \Rightarrow $ $ x,(x+4)+3,(x+4)=0 $

$ \Rightarrow $ $ (x+4)(x+3)=0 $

$ \Rightarrow $ $ x=-,3, $ $ -,4 $ II. $ 2y^{2}+11y+15=0 $

$ \Rightarrow $ $ 2y^{2}+6y+5y+15=0 $

$ \Rightarrow $ $ 2y,(y+3)+5,(y+3)=0 $

$ \Rightarrow $ $ (y+3)(2y+5)=0 $

$ \Rightarrow $ $ y=-,3, $ $ -\frac{5}{2} $