Question: Two vessels A and B contain milk and water mixed in the ratio 8: 5 and 5: 2, respectively. The ratio in which these two mixtures be mixed to get a new mixture containing $ 69\frac{3}{13}% $ milk is,
Options:
A) 2 : 7
B) 3 : 5
C) 5 : 2
D) 5 : 7
Show Answer
Answer:
Correct Answer: A
Solution:
- Let cost of 1 L milk be Rs. 1.
Milk in 1 L mixture in $ A=Rs.\frac{8}{13}L, $
CP of 1 L mixture in $ A=Rs.,\frac{8}{13} $
Milk in 1 L mixture in $ B=\frac{5}{7}L, $
CP of 1 L mixture in $ B=Rs.,\frac{5}{7} $
Milk in 1 L of final mixture
$ =( \frac{900}{13}\times \frac{1}{100}\times 1 )=\frac{9}{13}L $
Mean price $ =Rs.\frac{9}{13} $
By the rule of alligation, we have
$ \therefore $ Required ratio $ =\frac{2}{91}:\frac{1}{13}=2:7 $