Quantitative Aptitude Ques 2272

Question: A tap can empty a tank in 1 h. A second tap can empty in 30 min. If both the taps operate simultaneously, how much time is needed to empty the tank?

Options:

A) 20 min

B) 30 min

C) 40 min

D) 45 min

Show Answer

Answer:

Correct Answer: A

Solution:

  • 1 h = 60 min Rate of empty the tank by the two taps are $ \frac{1}{60} $ and $ \frac{1}{30} $ of the tank per minute, respectively. Rate of emptying the tank when both operate simultaneously $ =\frac{1}{60}+\frac{1}{30}=\frac{1+2}{60} $ $ =\frac{3}{60}=\frac{1}{20} $ of the tank per minute.

$ \therefore $ Time taken by the two taps together to empty the tank = 20 min

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