SATHEE: Quantitative Aptitude Ques 226

Quantitative Aptitude Ques 226

Question: In a right angled triangle PQR, PR is the hypotenuse of length 20 cm, $ \angle PRQ=30{}^\circ , $ then the area of the triangle is

Options:

A) $ 100\sqrt{3},cm^{2} $

B) $ 100/\sqrt{3},cm^{2} $

C) $ 50\sqrt{3},cm^{2} $

D) $ 25\sqrt{3},cm^{2} $

Show Answer

Answer:

Correct Answer: C

Solution:

$ \cos 30{}^\circ =\frac{QR}{PR}=\frac{QR}{20} $

$ \Rightarrow $ $ \frac{\sqrt{3}}{2}\times 20=QR $ (i) $ \sin 30{}^\circ =\frac{PQ}{PR}=\frac{PQ}{20} $
$ \Rightarrow $ $ \frac{1}{2}=\frac{PQ}{20} $

$ \therefore $ $ PQ=10 $ Area of $ \Delta PQR=\frac{1}{2}\times 10\times 10\sqrt{3}=50\sqrt{3},cm^{2} $

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Quantitative Aptitude Ques 226

Question: In a right angled triangle PQR, PR is the hypotenuse of length 20 cm, $ \angle PRQ=30{}^\circ , $ then the area of the triangle is

Options:

Answer:

Solution:

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