Quantitative Aptitude Ques 2253

Question: If $ a:b=c:d=e:f=1:2, $ then $ (pa+qc+re):(pb,+qd+rf) $ is equal to

Options:

A) $ p:(q+r) $

B) $ (p+q):r $

C) 2 : 3

D) 1 : 2

Show Answer

Answer:

Correct Answer: D

Solution:

  • $ \frac{a}{b}=\frac{c}{d}=\frac{e}{f}=\frac{1}{2} $
    $ \Rightarrow $ $ \frac{pa}{pb}=\frac{qc}{qd}=\frac{re}{rf}=\frac{1}{2} $

$ \Rightarrow $ $ \frac{pa+qc+re}{pb+qd+rf}=\frac{1}{2} $

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