Question: The vessels A and B contains acid and water in the ratio 4: 3 and 5: 3, respectively. Then, the ratio in which these mixtures to be mixed to obtain a new mixture in vessel C containing acid and water in the ratio 3 : 2 is
Options:
A) 5 : 8
B) 7 : 8
C) 7 : 5
D) 4 : 7
Show Answer
Answer:
Correct Answer: B
Solution:
- In Vessel A, part of acid $ =\frac{4}{7} $
In Vessel B, part of acid $ =\frac{5}{8} $
In Vessel C, part of acid $ =\frac{3}{5} $
By Alligation rule
$ \therefore $ Required ratio $ =\frac{1}{40}:\frac{1}{30}=35:40=7:8 $