Question: Walking at $ \frac{3}{4}th $ of his usual speed, a man reaches his office 20 min late. What is the time taken by him to reach the office at his usual speed?
Options:
A) 80 min
B) 70 min
C) 60 min
D) 50 min
Show Answer
Answer:
Correct Answer: C
Solution:
- Let usual speed of the man be x km/h.
Then, new speed $ =\frac{3}{4}x $
Let D is the distance to cover.
$ \frac{D}{\frac{3}{4}x}-\frac{D}{x}=\frac{20}{60} $
$ \Rightarrow $ $ \frac{4D}{3x}-\frac{D}{x}=\frac{20}{60} $
$ \Rightarrow $ $ \frac{D}{3x}=\frac{1}{3} $
$ \Rightarrow $ $ \frac{D}{x}=1h=60,min $