Quantitative Aptitude Ques 216

Question: If 5 engines consume 6 metric tonnes of coal when each is running 9 h a day, how many metric tonnes of coal will be needed for 8 engines, each running 10 h a day, it being given that 3 engines of the former type consume as much as 4 engines of the latter type?

Options:

A) $ 3\frac{1}{8} $

B) 8

C) $ 8\frac{8}{9} $

D) $ 6\frac{12}{25} $

Show Answer

Answer:

Correct Answer: B

Solution:

  • Let the required quantity of coal be x metric tonnes. More engines, More coal [Direct proportion] More hours per day, More coal [Direct proportion] More rate, More coal [Direct proportion] $ . \begin{matrix} Engines & 5:8 \\ Hours,per,day & 9:10 \\ Rate & \frac{1}{3}:\frac{1}{4} \\ \end{matrix}, }::6:x $

$ \therefore $ $ ( 5\times 9\times \frac{1}{3}\times x )=( 8\times 10\times \frac{1}{4}\times 6 ) $

$ \Rightarrow $ $ 15x=120,\Rightarrow ,x=8 $

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