SATHEE: Quantitative Aptitude Ques 2159

Quantitative Aptitude Ques 2159

Question: If $ A:B=\frac{1}{2}:\frac{1}{3}, $ $ B:C=\frac{1}{5}:\frac{1}{3}, $

then $ (A+B):(B+C) $ is equal to

Options:

A) 9 : 10

B) 6 : 15

C) 5 : 8

D) 15 : 16

Show Answer

Answer:

Correct Answer: D

Solution:

$ A:B=\frac{1}{2}:\frac{1}{3}=3:2=9:6 $ $ B:C=\frac{1}{5}:\frac{1}{3}=3:5=6:10 $

$ \Rightarrow $ $ A:B:C=9:6:10 $ Let $ A=9k, $ $ B=6k $ and $ C=10k $ Then, $ \frac{(A+B)}{(B+C)}=\frac{(9k+6k)}{(6k+10k)}=\frac{15k}{16k}=15:16 $

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Quantitative Aptitude Ques 2159

Question: If $ A:B=\frac{1}{2}:\frac{1}{3}, $ $ B:C=\frac{1}{5}:\frac{1}{3}, $

Options:

Answer:

Solution:

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