A) $ \frac{5\pi }{12} $
B) $ \frac{\pi }{3} $
C) $ \frac{\pi }{5} $
D) $ \frac{\pi }{6} $
Correct Answer: B
$ \Rightarrow $ $ 1+{{\tan }^{2}}\theta +{{\tan }^{2}}\theta =7 $ $ [\because {{\sec }^{2}}\theta =1+{{\tan }^{2}}\theta ] $
$ \Rightarrow $ $ 1+2{{\tan }^{2}}\theta =7 $
$ \Rightarrow $ $ 2{{\tan }^{2}}\theta =6 $
$ \Rightarrow $ $ {{\tan }^{2}}\theta =3 $
$ \therefore $ $ \tan \theta =\pm ,\sqrt{3} $ Since, $ 0\le \theta \le \frac{\pi }{2} $
$ \therefore $ $ \tan \theta =\sqrt{3} $ $ \theta =60{}^\circ =\frac{\pi }{3} $ [as $ \pi =180{}^\circ $ ]