Question: Two stations P and Q are at a distance of 160 km. Two trains start moving from P and Q to Q and P, respectively and meet each other after 4 h. If speed of the train starting from P is more than that of other train by 6 km/h, then find the speeds of both the trains, respectively.
Options:
A) 19 km/h, 13 km/h
B) 13 km/h, 9 km/h
C) 17 km/h, 23 km/h
D) 16 km/h, 10 km/h
E) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
- Let the speed of both trains be x km/h and
$ (x+6)km/h, $ respectively.
Then, according to the question,
$ 160=x\times 4+(x+6)\times 4 $
$ \Rightarrow $ $ 160=4x+4x+24 $
$ \Rightarrow $ $ 40=x+x+6 $
$ \Rightarrow $ $ 2x+6=40 $
$ \Rightarrow $ $ 2x=34 $
$ \therefore $ $ x=17 $
Hence, speeds of both the trains are $ 17km/h $ and $ (17+6)km/h $ i.e. $ 17km/h $ and $ 23,km/h. $