Question: A mixture of 40 L of milk and water contains 10% of water. How much water must be added to make the water 20% in the new mixture?
Options:
A) 10 L
B) 7 L
C) 5 L
D) 3 L
Show Answer
Answer:
Correct Answer: C
Solution:
- In a mixture of 40 L,
Water $ =\frac{40\times 10}{100}=4L $
According to the question,
If the quantity of water mixed be x L, then
$ (4+x)=(40+x)\times 20 $ %
$ \Rightarrow $ $ 4+x=\frac{(40+x)20}{100} $
$ \Rightarrow $ $ 5(4+x)=40+x $
$ \Rightarrow $ $ 20+5x=40+x $
$ \Rightarrow $ $ 4x=40-20=20 $
$ \therefore $ $ x=\frac{20}{4}=5L $