Quantitative Aptitude Ques 2135

Question: A mixture of 40 L of milk and water contains 10% of water. How much water must be added to make the water 20% in the new mixture?

Options:

A) 10 L

B) 7 L

C) 5 L

D) 3 L

Show Answer

Answer:

Correct Answer: C

Solution:

  • In a mixture of 40 L, Water $ =\frac{40\times 10}{100}=4L $ According to the question, If the quantity of water mixed be x L, then $ (4+x)=(40+x)\times 20 $ %

$ \Rightarrow $ $ 4+x=\frac{(40+x)20}{100} $

$ \Rightarrow $ $ 5(4+x)=40+x $
$ \Rightarrow $ $ 20+5x=40+x $

$ \Rightarrow $ $ 4x=40-20=20 $

$ \therefore $ $ x=\frac{20}{4}=5L $