Quantitative Aptitude Ques 2127

Question: Directions: In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer. [RBI (Assistant) Scale 2011]

I. $ x^{2}-10x+24=0 $
II. $ y^{2}-9y+20=0 $

Options:

A) If $ x>y $

B) If $ x\ge y $

C) If $ x<y $

D) If $ x\le y $

E) If $ x=y $ or the relationship cannot be established

Show Answer

Answer:

Correct Answer: B

Solution:

  • I. $ x^{2}-10x+24=0 $

$ \Rightarrow $ $ x^{2}-6x-4x+24=0 $
$ \Rightarrow $ $ x(x-6)-4(x-6)=0 $

$ \Rightarrow $ $ (x-4)(x-6)=0 $
$ \Rightarrow $ $ x=4, $ $ 6 $ II. $ y^{2}-9y+20=0 $

$ \Rightarrow $ $ y^{2}-5y-4y+20=0 $
$ \Rightarrow $ $ y(y-5)-4(y-5)=0 $

$ \Rightarrow $ $ (y-4)(y-5)=0 $
$ \Rightarrow $ $ y=4, $ $ 5 $ Hence, $ x\ge y. $