Quantitative Aptitude Ques 2127
Question: Directions: In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer. [RBI (Assistant) Scale 2011]
I. $ x^{2}-10x+24=0 $
II. $ y^{2}-9y+20=0 $
Options:
A) If $ x>y $
B) If $ x\ge y $
C) If $ x<y $
D) If $ x\le y $
E) If $ x=y $ or the relationship cannot be established
Show Answer
Answer:
Correct Answer: B
Solution:
- I. $ x^{2}-10x+24=0 $
$ \Rightarrow $ $ x^{2}-6x-4x+24=0 $
$ \Rightarrow $ $ x(x-6)-4(x-6)=0 $
$ \Rightarrow $ $ (x-4)(x-6)=0 $
$ \Rightarrow $ $ x=4, $ $ 6 $
II. $ y^{2}-9y+20=0 $
$ \Rightarrow $ $ y^{2}-5y-4y+20=0 $
$ \Rightarrow $ $ y(y-5)-4(y-5)=0 $
$ \Rightarrow $ $ (y-4)(y-5)=0 $
$ \Rightarrow $ $ y=4, $ $ 5 $
Hence, $ x\ge y. $
BETA
